Question

A man is watching the top of a 220 m tower from the ground. He is standing at a distance of 70m from the bottom of the tower. Find the angle of elevation of the tower with respect to the position of the man.​

Answer 1

Answer:

the answer is attached. you don't have to find the correct value,( I.e 73.34) I just looked it up on Internet .hope it helps

Answer 2

The angle of elevation of the tower with respect to the position of the man is about 72.35°.

Given,

Height of the tower = 220 m,

Distance between tower and man = 70 m.

To find,

The angle of elevation of the tower with respect to the man.

Solution,

Firstly, let the top of the tower be A, its bottom B, and the position of the man be C.

Let the angle of elevation, that is ∠ACB be $\theta$.

It can be seen that ABC will form a triangle, right-angled at B.

Now, in ΔABC, we can see,

AB = height of the tower = 220 m,

BC = distance between tower and man = 70 m, and

AC will be the hypotenuse.

Since ΔABC is a right triangle, we can use the trigonometric function $\tan \theta$, to find the angle of elevation θ.

Thus,

$\tan \theta=\frac{AB}{BC}$

$\implies \tan \theta=\frac{220}{70}$

$\implies \theta=\tan ^{-1} (\frac{22}{7})$

$\implies \theta= 72.3499$

⇒ θ ≈ 72.35°.

Therefore, the angle of elevation of the tower with respect to the position of the man is about 72.35°.