Question

A man jas ₹21 in the form of 50 pasa and 25 pasa coins. If the total no. Of coins are 52,find the no. Of coins of each type

Answer 1

Step-by-step explanation:

A man has Rs 21 in the form of 50 paise and 25 paise coins. If the total no of coins are 52. Multiply x + y = 52 by 50 and subtracted from 50x + 25y = 2100 . Putting this value in x + y = 52 .

Answer 2

Answer:

50 paisa coins = 32, 25 paisa coins = 20

Step-by-step explanation:

Let the number of 50 paisa coin be x

So, number of 25 paisa coin be 52 - x

Value of one 50 paisa coin = 50 paisa

Value of x 50 paisa coins = 50x paisa

Value of one 25 paisa coin = 25 paisa

Value of 52 - x coins = 25(52 - x)

Total money = Rs. 21 or 2100 Paisa

So,

Value of x coins of 50 paisa + Value of (52 - x) coins of 25 paisa = 210 paisa

50x + 25( 52 - x ) = 2100

50x + 1300 - 25x = 2100

25 x = 2100 - 1300

25x = 800

On dividing both sides by 25, we get

x = 32

Hence number of 50 paisa coins is 32

and number of 25 paisa coins = (52 - x) = (52 - 32) = 20