Question

A man jogs 190 metre in 48 second and another 250 metre in 62 second . Find his average speed in km/hr.

Answer 1

$<b>$Answer :

A man jogs = 190m

Time taken = 48sec
_________

Again, he jogs = 250m

Time taken = 62sec
_________

Average speed = ?

$D_1$ = 190m

$D_2$ = 250m

$T_1$ = 48sec

$T_2$ = 62sec

Average speed = $\\ \\ \frac{Total \: distance \: travelled}{Total \: time \: taken} \\ \\ => \frac{D_1 + D_2}{T_1 + T_2} \\ \\ => \frac{190 + 250}{48 + 62} \\ \\ => \frac{440}{110} \\ \\ => \frac{4}{1} \\ \\ => 4 m/sec$

To convert the speed into km/hr

$=> 4 \times \frac{18}{5} \\ \\ => \frac{72}{5} \\ \\ => 14.4 km/hr$

Tysm for the question!