A man jump on ground 20m then find how much he can jump more
Answers
This is a genuine case of the man's mass having nothing to do with tallness accomplished, and with his underlying and last speed. His last speed is zero when he achieves the tallness of 20m. The speeding up g is 9.81m/s^2. So we can utilize the kinematics condition here as pursues : v^2 = u^2 - 2as, where v is the last speed which is zero, u is the underlying speed, an is the gravitational acceleration(in this circumstance fills in as deceleration), and s is the tallness or the separation crossed. So how about we settle for u here : u^2 - 2as = 0, as v is zero, at that point u^2 = 2as, which gives you : u = (2as)^1/2. Connecting values for an and s will give you the appropriate response - m/s as the speed with which the man bounced upwards…