Question

A man kicks with his foot soccer ball initially at rest. the ball has a mass of 10.73 kg and a speed of 74 m/s in 11 micro seconds. find.a) what is the change in momentum b) what is the average force against the force during the impact​

Answer 1

$m = 10.73kg$

$u = 0$

$v = 75$

change in momentum

=mv-mu

=m(75-0)

=10.73×75

=804.75

$force = \frac{change \: in \: momentum}{time}$

$f = \frac{804.75}{11 \times {10}^{ - 6} }$

$f = 73.15 \times {10}^{6} newton$

I hope this helps

Answer 2

Answer:

change in momentum

=mv-mu

=m(74-0)

=10.73×74

=794.02

Force=change in momentum/11×10to the power 6

         =72.18*10to the power 6

I hope this helps

Explanation: