A man known to be victim of haemophilia marries a normal woman whose father was known to be a bleeder. Then it is expected that [AIIMS 1985; Pb. PMT 1999; CBSE PMT 2000]
A) All their children will be bleeders
B) Half of their children will be bleeders
C) One fourth of their children will be bleeders
D) None of their children will be bleeder
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● A man known to be victim of haemophilia which is called bleeder's disease marries a normal woman whose father was known to be a bleeder then the possibility for the children is half of their children will be breeders.
● This is because do the women is is normal but as her father is known for the disease she might be the carrier of the gene causing the disease.
● Hence half of the children of of the case will be diagnosed for leaders disease.
● Because disease causing haemophilia gene is present on X chromosome.
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As the parents produce the children, the probability of the children being a bleeder is half.
Explanation:
- Haemophilia is a allosomal recessive disease. Its due to modification of the gene that is present on the X chromosomes.
- In case of male, there is only one X chromosome, so presence of the gene will make the person haemophilic.
- But in case of females the presence of haemophilia gene on both the chromosomes will make them haemophilic.
- The father has haemophilia, so has the gene on the X chromosome. The mother doesn’t have haemophilia, but her father was haemophilic.
- So she is a carrier. Thus with pedigree analysis, we can see that half of the boys and girls each will have the probability of being haemophilic.
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