Question

a man land 60000 partly at 5% and the rest at 4% simple interest if the total annual interest is rupees 2560 what was the amount land at 4% ​

Answer 1

$\sf\purple{Given :-}$

a man land 60000 partly at 5% and the rest at 4% simple interest if the total annual interest is rupees 2560 what was the amount land at 4%

$\sf\purple{Solution :-}$

Let the amount lent at $\sf{4 \:\%}$ be ₹ x.

Then, amount lent at $\sf{5\:\%}$ = $\sf{60000 - x}$

$\rm\blue{According\:to\:the\:question\:,}$

$\implies{\sf\frac{(60000 \: - x) \: \times 5 \times 1 }{100} + \frac{x \: \times \: 4 \: \times \: 1}{100}}$

$\sf\implies{300000 \: - 5x \: + 4x = 256000}$

$\sf\implies {x \: = \: 300000 \: - 256000}$

$\sf{\boxed{\red{44,000\:Ans\:!}}}$

$\begin{lgathered}\boxed{\underline{\underline{\bigstar\:\bf\:Extra\:Shots\:\bigstar}}}\\\end{lgathered}$

$\begin{lgathered}\tt 1) Profit = SP - CP \\\end{lgathered}$

$\begin{lgathered}\tt 2) Loss = CP - SP \\\end{lgathered}$

$\begin{lgathered}\tt 3) Profit\% = (Profit \:in \:Rs.)*100/CP\\\end{lgathered}$

$\begin{lgathered}\tt 4) Loss\% = (Loss \:in \:Rs.)*100/CP\\\end{lgathered}$

$\begin{lgathered}\tt 5) SP = CP*(100+P\%)/100\\\end{lgathered}$

$\begin{lgathered}\tt 6) SP = CP*(100-L\%)/100\\\end{lgathered}$

$\begin{lgathered}\tt 7) CP = SP*100/(100+P\%)\\\end{lgathered}$

$\begin{lgathered}\tt 8) CP = SP*100/(100-L\%)\\\end{lgathered}$

$\begin{lgathered}\tt 9) Discount =MP - SP\\\end{lgathered}$

$\begin{lgathered}\tt 10) Discount\%=(Discount \:in \:Rs.)*100/MP\\\end{lgathered}$

$\begin{lgathered}\tt 11) MP = SP*100/(100-D\%)\\\end{lgathered}$

Answer 2

Given :-

• a man land 60000 partly at 5% and the rest at 4% simple interest if the total annual interest is rupees 2560 what was the amount land at 4%

Solution :-

• Let the amount at 5% be ₹ a
• then, the amount at 4% = ₹(60000 - a)

$\rm\red{The\: question\: says,}$

→ (60000 - a) × 5 / 100 + a × 4 / 100 = 2560

→ 3,00,000 - 5a + 4a = 2,56,000

→ a = 3,00,000 - 2,56,000 = ₹ 44,000

Thank You !!