Math, asked by himanishrimali, 11 months ago

a man leads 10,00,000 at 10% for 2 years complounded annually .another man leads the same amount at the asame rate of interest at the sane time but interest to be compounded half yearly .who will gain more interest and how much give me step by step explanation and with the correct ans i will make you as brainlist​

Answers

Answered by surajdubey48
2

Step-by-step explanation:

1st man

principal=1000000

rate=10%

time=2year

amount=P(1+r/100)^t

A=1000000(1+10/100)^2

A=1000000*121/100

A=1210000

CI=A-P

CI=1210000-1000000

CI=210000

2nd man

p=1000000

r=10%p.a. 5%hy

time=2year 4hy

A=1000000(1+5/100)^4

A=1000000*194481/160000

A=194481*100/16

A=1215506.25

CI=1215506.25-1000000

CI=215506.25

2nd man got more interest by 5506.26

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