a man leaves 1/2 of his property to his wife, 1/3 to his son and the remaining to his daughter. if the daughter's share is rs.5,000, how much money did the man leave? how much money did his wife get? what is his son's share?
Answers
Given,
Wife got 1/2 of the man's property.
Son got 1/3 of the man's property.
Remaining share is given to the daughter which has a value of rs. 5000
To find,
Total amount of the property. Amount of wife's share and amount of son's share.
Solution,
Let,the total amount of property = rs. x
So, wife got = x × ½ = rs. x/2
And, son got = x × ⅓ = rs. x/3
Remaining property = {x-(x/2+x/3)} = (x-5x/6) = rs. x/6
Now,if we compare the value of the remaining property that we have calculated and the value of the remaining property that is given in the question,then we will get the following mathematical equation,
x/6 = 5000
x = 30000
Total property = rs. 30000
Wife got = 30000 × ½ = rs. 15000
Son got = 30000 × ⅓ = rs. 10000
Hence,the total property of the man is rs.30000.The wife and the son got rs. 15000 and rs. 10000 respectively.
That's the answer of the question
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