Question

a man leaves 1/2 of his property to his wife, 1/3 to his son and the remaining to his daughter. if the daughter's share is rs.5,000, how much money did the man leave? how much money did his wife get? what is his son's share?​

Answer 1

Answer:

the man leave the rupees 30,000

if 1/ 2x + 1/3x +5000= x

unsolving this equation we get x value 30,000

the wife gets 15,000

the son get 10,000 rupees

Answer 2

Question

A man leaves 1/2 of his property to his wife, 1/3 to his son and the remaining to his daughter. If the daughter's share is Rs.15,000. How much money did the man leave ? How much money did his wife get ? What is his son's share ?

Given

• A man leaves his property to his wife. 1/3 to his son and the remaning to his daughter.
• The daughter's share is Rs.15000.

Required to Find

• How much money did the man leave ?
• How much money did his wife get?
• What is his son's share?

Solution

Let the total money of thean be Rs. x

$\large \sf \: money \: got \: by \: wife \: = rs. \dfrac{x}{2}$

$\sf \large \: money \: got \: by \: son \: = rs. \frac{x}{3}$

Money got by daughter = Rs. 15,000

$\\ \sf \large \: x - (\dfrac{x}{2} + \dfrac{x}{3}) = 15000$

$\\ \sf \large \implies \dfrac{6x - 3x - 2x}{6} = 15000$

$\\ \sf \large \dfrac{x}{6} = 15000$

x = 90,000

Therefore , total money that man leaves is Rs. 90,000.

$\\ \sf \large \: now \: share \: of \: wife \: rs. \dfrac{x}{2} = Rs. \dfrac{90000}{2} = Rs. \: 45000$

$\\ \sf \large \: and \: share \: of \: son \: = Rs. \dfrac{x}{3} = Rs. \dfrac{90000}{3} = rs.30000$