Math, asked by snehash48, 11 months ago

A man leaves 2/3 of his property for his wife and 1/5 of his property for his son and the remaining for his daughter. What part does his daughter receive.​

Answers

Answered by shobhitjhakhal18
3

Step-by-step explanation:

Wife shares =

2/3∗4/4=2/3∗4/4=

8/128/12

Son's share =

1/4∗3/3=1/4∗3/3=

3/123/12

Daughter's share=

1–8/12–3/12=1–8/12–3/12=

1/12

it will helps u

Answered by 16MonksS
0

Answer:

2/5 of the parents property hopes this helps you

Step-by-step explanation:

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