Question

A man leaves a point p at 6

a.m. and reaches the point q at 10

a.m. another man leaves the point q at 8

a.m. and reaches the point p at 12 noon. at what time do they meet

Answer 1

Answer:

They will meet at 9 am

Step-by-step explanation:

Step 1: Given Data

A Man leaves a point p = 6 a.m

Reaches a point q=10 a.m

Step 2: Another man leaves a point q= 8 a.m

Reaches a point p=12 Noon

Step 3: Let first man takes 4 hours to cover the distance

Therefore velocity=2 x s/4 km/hr

   =s/2 km/hr

Step 4: Second Man takes 4 hrs to cover the distance = 2 x s/4 km/hr =s/2 km/hr

Step 5: As velocity of both are same, both will cover same distance s/2 (km) and it will take 1 hour to cover

Step 6: The relative speed of both men is double of individual speed.

Time = Distance/Speed = (1/2)/2 = 1 hour.

They meet at 8 + 1 = 9:00 AM.

Answer 2

Answer:

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Step-by-step explanation:

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