Question

a man leaves half his property to his wife 1/3 to hid son and remaining to his daughter .if the daughters share is rupees 15000 how much did the man left??​

Answer 1

Answer:

let the property be x

wife = half of his property = x/2

son   = x/2 -x/3= x/6 (remaning of his mother )

so, daughter = x-(x/2 + x/6)

                   = x – 4x/6

                   = 2x/6=x/3

15000 =  x/3

Then x = 15000 * 3  = 45000

So property amount = Rs.45000

Wife                        = 45000/2 = 22500Rs

Son                         = 45000/6 = 7500 Rs.

& daughter              = 45000/3 = 15000Rs.      

Step-by-step explanation:

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Answer 2

Answer:

$\huge\bf{\underline{{Answer }}} -$

Let the total money of the man be Rs. x.

Money got by wife = Rs. X/2

Money got by son = Rs. X/3

Money got by daughter = Rs. 15,000

$x \: - ( \frac{x}{2} + \frac{x}{3}) = 15000$

$⟹ \: \frac{6x - 3x - 2x \: }{6} = 15000$

$⟹ \: \frac{x}{6} = 15000$

$x \: = 90000$

Therefore, total money that man leaves is Rs. 90,000..