Question

a man leaves half his property to his wife , one third of the remaining to his son and the rest to his daughter . if daughter's share is rupees 15000 , how much did the man leave ? how much did his wife and son get

Answer 1

       let the property be x

wife = half of his property = x/2

son   = x/2 -x/3= x/6 (remaning of his mother )

so, daughter = x-(x/2 + x/6)

                    = x – 4x/6

                    = 2x/6=x/3

15000 =  x/3

Then x = 15000 * 3  = 45000

So property amount = Rs.45000

 Wife                        = 45000/2 = 22500Rs

 Son                         = 45000/6 = 7500 Rs.

& daughter              = 45000/3 = 15000Rs.                     

Answer 2

Property =x

Property given to wife=x/2

Property given to son =x/3

Remaining ,

x/2-x/3=x/6

A. T. Q,

Daughter share=>

x-x/2+x/6=15000

x-3x+x/2=15000

x/1-4x/6=15000

6x-4x/6=15000

2x/6=15000

x/3=15000

x=15000×3=45000

To his wife son....

Son gets,

x/2=15000

x=15000×2

X=30000

Hence, Total property

=45000+30000+15000

=90000