Math, asked by Akramkhan9910, 11 months ago

A man leaves half of his property for his wife one third for his daughter and remaining for his son if his son's share is rs 80000 how many money did he leave and how much money did his wife get

Answers

Answered by kim85
3

Answer:

for wife = x/2 rs

for daughter = x/3

for son = x- (x/2+x/3)rs = x/6 rs

a/q

x/6 =80000

x = 480000 rs

for wife = 240000 rs

he leaves 4,80,000 rs

for wife 2,40,000 rs

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