Math, asked by angelsinha2006, 7 months ago

A man leaves half of his property for his wife, one third for his daughter and remaining for his son. If son's share is 60,000, how much money did he leave and how much money did his wife and son get ? ​

Answers

Answered by maghaananthi
1

Answer:

₹360000, ₹ 180000, ₹120000

Step-by-step explanation:

1/2+1/3

=3/6+2/6

=5/6 1/6=60000

thus, 6/6= 60000x6

              = 360000(Total money)

wife: 3/6=60000x3=180000

daughter(NOT SON CUZ THE AMT SON GOT WAS ALREADY GIVEN):

2/6= 60000x2

     = 120000

Ans:  how much money did he leave --> ₹360000

        how much money did his wife and daughter ( not son) get --> wife: ₹180000 daughter: ₹120000

Answered by NishchalbSingh
1

Solution.Let Rs.x be the money left by the man.

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