A man leaves half of his property to his wife one third of his son and remaining for his daughter.if daughter share is 50000 then how much property did his wife get.and what is his son share?
Answers
Answer:
Mother = 1,50,000
Son = 1,00,000
Step-by-step explanation:
Given :
- Share of the man's wife = ½
- Share of son's property = ⅓
- Share of daughter = 50,000
To find :
- Share of son
- Share of mother
Let total amount be X
Share of daughter = total share - (share of son + share of mother)
Share of daughter = X-(½X + ⅓X)
Share of daughter = X-(3/6 X + 2/6X)
50,000 = X-(5/6X)
50,000 = 6/6 X - 5/6 X
50,000 = 1/6 X
3,00,000 = 1X
X = 3,00,000 / 1
X = 3,00,000
Share of mother = ½X = ½×3,00,000 = 1,50,000
Share of son = ⅓X = ⅓×3,00,000 = 1,00,000
Share of mother is 1,50,000 and share of son is 1,00,000
Answer:
let the property be x
let the property be xwife = half of his property = x/2
let the property be xwife = half of his property = x/2son = x/2 -x/3= x/6 (remaning of his mother )
so, daughter = x-(x/2 + x/6)
= x – 4x/6
= 2x/6=x/3
15000 = x/3
Then x = 15000 * 3 = 45000
Then x = 15000 * 3 = 45000So property amount = Rs.45000
Wife = 45000/2 = 22500Rs
Son = 45000/6 = 7500 Rs.
& daughter = 45000/3 = 15000Rs.
Sumitprusty Ambitious
Property =x
Property given to wife=x/2
Property given to son =x/3
Remaining ,
x/2-x/3=x/6
A. T. Q,
Daughter share=>
x-x/2+x/6=15000
x-3x+x/2=15000
x/1-4x/6=15000
6x-4x/6=15000
2x/6=15000
x/3=15000
x=15000×3=45000
To his wife son....
Son gets,
x/2=15000
x=15000×2
X=30000
Hence, Total property
=45000+30000+15000
=90000