Math, asked by parthawasthiyo4, 1 year ago

A man leaves half of his property to his wife, two third of the remainder to his son and the remaining Rs. 25000 to his daughter. How much money did the man leave for his wife and what is his sons share?

Answers

Answered by abhinavmathsscience
1
let the property the man had be x
therefore,property wife got will be x/2
property the son will get be 2/3(x-x/2)=
=2/3{(2x-x)/2}
=2/3(x/2)
=x/3
therefore ,daughter will get 25000
total property of wife son and daughter is x
x/2+x/3+25000=x
x-x/3-x/2=25000
(6x-2x-3x)/6=25000
x/6=25000
x=25000*6
x=150000
hence money of man=150000
money wife got=150000/2=75000
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