Question

A man leaves home at 7.45 a.m and cycles to work 6 1/4 km away. He arrives at work at 8.10 a.m What is his average speed?​

Answer 1

Answer: 25/6 m/s or 15 km/hr

Step-by-step explanation:

To find the average speed , we need the total distance covered and the total time taken.

Avg. speed  - Total distance / Total time

Total distance covered = $6\frac{1}{4} km =\frac{25}{4} km$

Total time taken = 8:10 - 7:45 = 490 min - 465 min = 25 mins

Convert the distance and the time in the standard units of measurement. (It is not compulsory but it it better to do this, so that you get your answer in m/s)

$\frac{25}{4} km = 6250 m$

$25 min = 1500 sec$

∴ Avg. speed = $\frac{distance}{time} =\frac{6250 m}{1500 s} = \frac{25m}{6s}$

∴ The man's average speed = 25/6 m/s or approx. 4.16 m/s

(Note - 25/6 m/s = 15 km/hr)

Answer 2

Answer:

To find the average speed , we need the total distance covered and the total time taken.

Avg. speed - Total distance / Total time

Total distance covered = ⁶ 1 / 4 km = 25 / 4 km

Total time taken = 8:10 - 7:45 = 490 min - 465 min = 25 mins

Convert the distance and the time in the standard units of measurement. (It is not compulsory but it it better to do this, so that you get your answer in m/s)

25 / 4 km = 6250 m

25 min = 1500 sec

∴ Avg. speed = Distance / time = 6250 m / 1500 s

= 25 m / 6 sec

∴ The man's average speed = 25/6 m/s or approx. 4.16 m/s

(Note - 25/6 m/s = 15 km/hr)

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