A man leaves office daily at 7pm a driver with car comes from his home to pick him from office and bring back home one day he gets free at 5:30 and instead of waiting for driver he starts walking towards home. in the way he meets the car and returns home on car he reaches home 20 minutes earlier than usual. in how much time does the man reach home usually?
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2 years agoHelpfull: Yes(0) No(2)
If Man reaches to his house befour 20 minutes by his usual time ,means he meet his vehicle befour 10 min of his usual time. The distance walk by him in 1:30hr is equal to distance cover by the vehicle in 10 min. hence 1:30-0:10= 1:20 mins........means he reach at home by the 8:30PM usually
2 years agoHelpfull: Yes(0) No(2)
If Man reaches to his house befour 20 minutes by his usual time ,means he meet his vehicle befour 10 min of his usual time. The distance walk by him in 1:30hr is equal to distance cover by the vehicle in 10 min. hence 1:30-0:10= 1:20 mins........means he reach at home by the 8:30PM usually
If Man reaches to his house befour 20 minutes by his usual time ,means he meet his vehicle befour 10 min of his usual time. The distance walk by him in 1:30hr is equal to distance cover by the vehicle in 10 min. hence 1:30-0:10= 1:20 mins........means he reach at home by the 8:30PM usually
2 years agoHelpfull: Yes(0) No(2)
If Man reaches to his house befour 20 minutes by his usual time ,means he meet his vehicle befour 10 min of his usual time. The distance walk by him in 1:30hr is equal to distance cover by the vehicle in 10 min. hence 1:30-0:10= 1:20 mins........means he reach at home by the 8:30PM usually
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