A man left 1/2 of his money to his wife, 2/5 of what remained to his son, and ₱40,000 more than 1/2 of what then remained to his daughter. The remaining money was shared equally by his 2 nieces. If each niece has an equal share of ₱47,500, how much money did the man leave behind?
Answers
Given : A man left 1/2 of his money to his wife,
2/5 of what remained to his son, and
₱40,000 more than 1/2 of what then remained to his daughter.
The remaining money was shared equally by his 2 nieces.
Each niece has an equal share of ₱47,500,
To Find : how much money did the man leave behind
Solution:
Amount = 100x ₱
For his wife = (1/2) 100x = 50x ₱
Remaining = 100x - 50x = 50x ₱
For Son = (2/5) 50x = 20x ₱
Remained = 50x - 20x = 30x ₱
Gave to Daughter = 40000 + (1/2) 30x = 15x + 40000 ₱
Remaining = 30x - ( 15x + 40000) = 15x - 40000 ₱
The remaining money was shared equally by his 2 nieces.
=> (15x - 40000)/2 = 47500
=> 15x - 40000 = 95000
=> 15x = 135000
=> x = 9000
100x = 900000
man leave behind 900000 ₱
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