Math, asked by Prayash1280, 1 year ago

a man left 1/2 of his property to his wife,5/7 of his remainder to his daughter.he gave rest to his son.who recieved 42000.how much was his original property worth?

Answers

Answered by Geniusman
2
294000 OK
please mark brainiest
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Answered by wifilethbridge
2

Answer:

Rs. 294000

Step-by-step explanation:

Let his original property worth be x

Since we are given that a man left 1/2 of his property to his wife.

So, Wife's share =\frac{x}{2}

Remaining = x-\frac{x}{2} =\frac{x}{2}

Now we are given that he gave 5/7 of his remainder to his daughter.

So, Daughter's Share = \frac{5}{7} \times \frac{x}{2} = \frac{5x}{14}

Now reaming = \frac{x}{2}-\frac{5x}{14} =\frac{2x}{14}

we are given that he gave rest to his son worth Rs. 42000

So, 42000=\frac{2x}{14}

42000=\frac{x}{7}

42000 \times 7=x

294000=x

Hence his original property worth is Rs. 294000

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