Question

a man left 1/2 of his property to his wife,5/7 of his remainder to his daughter.he gave rest to his son.who recieved 42000.how much was his original property worth?

Answer 1

294000 OK
please mark brainiest

Answer 2

Answer:

Rs. 294000

Step-by-step explanation:

Let his original property worth be x

Since we are given that a man left 1/2 of his property to his wife.

So, Wife's share =$\frac{x}{2}$

Remaining = $x-\frac{x}{2} =\frac{x}{2}$

Now we are given that he gave 5/7 of his remainder to his daughter.

So, Daughter's Share = $\frac{5}{7} \times \frac{x}{2} = \frac{5x}{14}$

Now reaming = $\frac{x}{2}-\frac{5x}{14} =\frac{2x}{14}$

we are given that he gave rest to his son worth Rs. 42000

So, $42000=\frac{2x}{14}$

$42000=\frac{x}{7}$

$42000 \times 7=x$

$294000=x$

Hence his original property worth is Rs. 294000