a man left 1/2 Of his propertyto his wife.He divided the remaining property equally amongst 5 of his children.how much did each child get
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Answer:
Step-by-step explanation:
Let amount of money be x
Then the wife got x/2 of the money.
Remaining money
=x - x/2
=x/2
Each child got 1/3 of x/2
=1/3 * x/2
=x/6
So, each child got one sixth of the total money
Answered by
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Answer:
let amount of property be x
he's wife get 1/2 that is x/2
remaining property
=x-x/2
=x/2
each of his children get x/5 of x/2
=x/5*x/2
=x/10
then each of his children get 1/10 of the property
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