Math, asked by mamatagupta26040, 1 month ago

a man left 1/2 Of his propertyto his wife.He divided the remaining property equally amongst 5 of his children.how much did each child get​

Answers

Answered by avabooleav
0

Answer:

Step-by-step explanation:

Let amount of money be x

Then the wife got x/2 of the money.

Remaining money

=x - x/2

=x/2

Each child got 1/3 of x/2

=1/3 * x/2

=x/6

So, each child got one sixth of the total money

Answered by madugunducharan
0

Answer:

let amount of property be x

he's wife get 1/2 that is x/2

remaining property

=x-x/2

=x/2

each of his children get x/5 of x/2

=x/5*x/2

=x/10

then each of his children get 1/10 of the property

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