a man left 25% of his money to his mother, 55% to his doughter and the remaining rupees 9000 to his brother. how much money did he have? find the shares of his mother and daughter.
Answers
Answered by
3
Let the total money be x
A.T.S.
25% of x + 55% of x +9000= x
25x/100+ 55x/100+9000= x
x/4 + 11x/20 +9000=x
(5x+11x)/20=x-9000
16x/20=x-9000
16x=20(x-9000)
16x=20x-180000
16x-20x=-180000
-4x=-180000
4x=180000
x=180000/4
x= 45000
So the man had a total of 45,000 rupees
Mother's shares= 25% if x
= 25/100*45000
= 11,250 rupees
Daughters share=55% of x
=55/100*45000
= 24,750
CONCLUSION
Total money man had= 45,000 rupees
Mother's shares= 11,250 rupees
Daughters share= 24,750 rupees
PLEASE MARK THIS ANSWER AS BRAINLIEST IF YOU FOUND IT HELPFUL!!
A.T.S.
25% of x + 55% of x +9000= x
25x/100+ 55x/100+9000= x
x/4 + 11x/20 +9000=x
(5x+11x)/20=x-9000
16x/20=x-9000
16x=20(x-9000)
16x=20x-180000
16x-20x=-180000
-4x=-180000
4x=180000
x=180000/4
x= 45000
So the man had a total of 45,000 rupees
Mother's shares= 25% if x
= 25/100*45000
= 11,250 rupees
Daughters share=55% of x
=55/100*45000
= 24,750
CONCLUSION
Total money man had= 45,000 rupees
Mother's shares= 11,250 rupees
Daughters share= 24,750 rupees
PLEASE MARK THIS ANSWER AS BRAINLIEST IF YOU FOUND IT HELPFUL!!
Answered by
0
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