Question

A man left 32% of his property to his wife,30% to his elder son, 28% to his younger son and the rest to his daughter. If the daughter's share is rupees 75000, find
a} the value of the man's property
b} the wife's share
c} the total share is the two sons​

Answer 1

Answer:

a). rupees 750000.

b).Rupees 240000

c).Rupees 435000

Step-by-step explanation:

the daughter gets 10 %

100-(32+30+28)=100- 90=10.

10% of man's total proerty is rs 75000 . (a/c to question)

a).

then x= (75000× 100)/10 =rs 750000 .

b).

32% of 750000 = rs 240000

c).

share of two sons =30 + 28 =58%= rs 435000