A man left 32% of his property to his wife,30% to his elder son, 28% to his younger son and the rest to his daughter. If the daughter's share is rupees 75000, find
a} the value of the man's property
b} the wife's share
c} the total share is the two sons
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Answer:
a). rupees 750000.
b).Rupees 240000
c).Rupees 435000
Step-by-step explanation:
the daughter gets 10 %
100-(32+30+28)=100- 90=10.
10% of man's total proerty is rs 75000 . (a/c to question)
a).
then x= (75000× 100)/10 =rs 750000 .
b).
32% of 750000 = rs 240000
c).
share of two sons =30 + 28 =58%= rs 435000
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