Question

A man left 32% of his property to his wife, 30% to his elder son, 28% to his younger son and the rest to his daughter. If the daughters share is rupees 75000. Find a) the value of the man's property, b)the wife share, c) the total share of the two sons

Answer 1

First, we find the percentage of the daughter's share: 100-32-30-28=10%

So we can conclude that 75000 rupees is 10% of the share. So we multiply that amount by 10 to find 100% (the total share/property amount).

a) 75000x10= 750 000 rupees

b) 75 000/10 x 32= 240 000 rupees

c) 28+30= 58%

75 000/10 x 58=435 000 rupees