Math, asked by dhruvmahajan286, 29 days ago

a man left 50%of his assets for his wife 20% of the remaining for the three sons and remaining for daughter if the daughter got 5.5 lakh find total assets of the man​

Answers

Answered by tennetiraj86
3

Step-by-step explanation:

Given :-

A man left 50% of his assets for his wife.

20% of the remaining for the three sons.

Remaining for his daughter .

His daughter got 5.5 lakh rupees

To find :-

Total assets of the man .

Solution :-

Let the total value of assets of the man be Rs. X

Value of the given assets for his wife

= 50% of the total assets

= 50% of X

= 50% × X

= (50/100)×X

= (1/2)×X

= Rs. X/2

His wife got Rs. X/2.

Value of the remaining assets

= X-(X/2)

= Rs. X/2

Value of the given assets for the three sons = 20% of the remaining assets

= 20% of X/2

= (20/100)×X/2

= (1/5)×(X/2)

= Rs. X/10

Three sons got Rs. X/10

Value of the remaining assets

= (X/2)-(X/10)

LCM of 2 and 10 = 10

= (5X-X)/10

= 4X/10

= Rs. 2X/5

Value of the given assets for his daughter

= Rs. 2X/5

According to the given problem

The amount is given to his daughter

= Rs.5.5 lakh

= 5.5×100000

= Rs. 550000

Therefore, 2X/5 = 550000

=> 2X = 550000×5

=> 2X = 2750000

=> X = 2750000/2

=> X = Rs. 1375000

Therefore, Total value of assets

= Rs. 13,75,000

Answer:-

The value of the total assets of the man is Rs. 13,75,000

Check :-

Total value of assets = Rs. 13,75,000

50% of the assets = 1375000/2

= Rs.687500

The money his wife got Rs. 687500

Remaining assets = Rs. 687500

The assets given to his sons = 20% of the remaining

= 20% of 687500

= (20/100)×687500

=687500/5

= Rs. 137500

Remaining value of assets is given to his daughter = 687500-137500

= Rs. 550000

= Rs. 5.5 Lakh

Verified the given relations in the given problem.

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