a man left 50%of his assets for his wife 20% of the remaining for the three sons and remaining for daughter if the daughter got 5.5 lakh find total assets of the man
Answers
Step-by-step explanation:
Given :-
A man left 50% of his assets for his wife.
20% of the remaining for the three sons.
Remaining for his daughter .
His daughter got 5.5 lakh rupees
To find :-
Total assets of the man .
Solution :-
Let the total value of assets of the man be Rs. X
Value of the given assets for his wife
= 50% of the total assets
= 50% of X
= 50% × X
= (50/100)×X
= (1/2)×X
= Rs. X/2
His wife got Rs. X/2.
Value of the remaining assets
= X-(X/2)
= Rs. X/2
Value of the given assets for the three sons = 20% of the remaining assets
= 20% of X/2
= (20/100)×X/2
= (1/5)×(X/2)
= Rs. X/10
Three sons got Rs. X/10
Value of the remaining assets
= (X/2)-(X/10)
LCM of 2 and 10 = 10
= (5X-X)/10
= 4X/10
= Rs. 2X/5
Value of the given assets for his daughter
= Rs. 2X/5
According to the given problem
The amount is given to his daughter
= Rs.5.5 lakh
= 5.5×100000
= Rs. 550000
Therefore, 2X/5 = 550000
=> 2X = 550000×5
=> 2X = 2750000
=> X = 2750000/2
=> X = Rs. 1375000
Therefore, Total value of assets
= Rs. 13,75,000
Answer:-
The value of the total assets of the man is Rs. 13,75,000
Check :-
Total value of assets = Rs. 13,75,000
50% of the assets = 1375000/2
= Rs.687500
The money his wife got Rs. 687500
Remaining assets = Rs. 687500
The assets given to his sons = 20% of the remaining
= 20% of 687500
= (20/100)×687500
=687500/5
= Rs. 137500
Remaining value of assets is given to his daughter = 687500-137500
= Rs. 550000
= Rs. 5.5 Lakh
Verified the given relations in the given problem.