A man left half his property to his wife one third to his son and the remaining to his daughter if daughter share is Re15000 how much did the man leave? how much money did his wife get?find the share of his son
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Answered by
35
Answer:
Property = Rs 90,000.
Wife= Rs 45,000
Son = Rs 30,000
Step-by-step explanation:
Fraction of the property given to wife = 1/2 (Given)
Fraction of the property given to son = 1/3 (Given)
Find the fraction of the property given to daughter:
Fraction = 1 - 1/2 - 1/3 = 1/6
Find the property:
Fraction given to daughter = 1/6
Shares given to daughter = Rs 15,000
1/6 of the property = Rs 15,000
6/6 of the property = 15,000 x 6 = Rs 90,000
Find the amount each got:
Daughter = Rs 15,000 (Given)
Wife = 1/2 x 90,000 = Rs 45,000
Son = 1/3 x 90,000 = Rs 30,000
Answer: The property is Rs 90,000. Wife got Rs 45,000 and Son got Rs 30,000
Answered by
6
A Man Shares His Half Of His Property To his Wife One Third To his Son And The Remaining Part To His
Daughter , Also Given That Share Of Daughter Is ₹ 15,000 , Now We Need To Find How Much Did The Man
Leave And also we Need to Find Shares Of wife And His son.
So Now Let's Move For Solution ..
Now According To Question
Now By Putting Values Of Wife's And Son's Property As 1/2 And 1/3 Respectively We Have..
Now by Taking LCM And Solving The bracket We Have ➡️
That Is
. -------- (1)
Now in Question It's Given that
--------- (2)
Now From 1 And 2 We Have ➡️
That Is
Now Taking 1/6 To RHS We Have ➡️
That Is
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