Math, asked by veluyuva, 1 year ago

a man left one half of his property to his wife one third to his son and remaining for his daughter.if the daughter 's share is Rs 60000 then how much money did the man have?

Answers

Answered by devil9311
11
1/2 - 1/3 = 1/6
1/6 = 60000
property = x
X*1/6 = 60000
x = 360000
Total property = 360000
Answered by prefectone
20
hii mate here is the answer to your question-
let, the total property of the man be x.
he left one half of that property to his wife =x/2.
he left one-third property to his son =1/3×x=x/3.
therefore , remaining property=x -{x/2+x/3}
=x-5x/6
=x/6.


according to the question, x/6=60000.
therefore, x=360000.
hope this helps you
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prefectone: plzz mark me brainliest
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