a man left two thirds of his property to his wife,one fourth to his daughter,and Rs. 15000 to his son. How much money did the man have?
ALSO,
ram's age is 4 times that of his son.five years ago,he was 9 times the age of his son.what are their ages?
Answers
Answered by
6
2/3+1/4=11/12
rest=1_11/12=1/12
1/12th of his property =15000
therefore the man has 15000 ×12=180000
rest=1_11/12=1/12
1/12th of his property =15000
therefore the man has 15000 ×12=180000
vasundhara09122006:
Thank you!!
Answered by
6
Hey mate!!
Here's your answer
1) let the property of the man = Rs x
amount wife get = Rs x /3
amount daughter get = Rs x / 4
remaining amount = Rs 15000
x - x / 3 - x / 4 = 15000
( 12 x - 4x - 3x ) / 12 = 15000
5x / 12 = 15000
x = ( 15000 × 12 ) / 5
x = 3000 × 12
x = 36000
Therefore ,
The total amount the man left = x = Rs 36000
2) let son's age = x
and ram's age = 4x
5 years ago
ram's age = 4x - 5
son's age = x - 5
4x - 5 = 9(x - 5)
4x -5 = 9x - 45
45 - 5 = 9x -4x
40 = 5x
x = 40/5 = 8
Therefore,
son's age = x = 8
ram's age = 4x = 4*8 = 32
Hope it helped you....Mark me as brainliest.....
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