Question

a man lent a part of ₹30000 at 10% and the remaining at 8% simple intrest. the total intrest he received after 3 years is ₹8280.calculate the amount he lent at 10%. Plz help me with this question

Answer 1

Intrest of money lent at 10 ℅=30000 ×10×3/100
=9000
Intrest of money lent at 8 ℅ = 30000×8× 3 /100
=7200

Answer 2

Answer:

He lent 18000 rupees at 10%.

Step-by-step explanation:

Given,total amount is 30000 rupees and he lent a part of 30000 at 10% and remaining at 8% at simple interest.

Let he lent x part at 10% .

So,it is clear he remaining part is (30000-x) at 8%.

We know by simple interest rule,

Simple interest $= \frac{prt}{100}$

In first case,

$p = x \\ r = 8\% \\ t = 3 \: years$

So, simple interest

$= \frac{x \times 10 \times 3}{100} \\ = \frac{x \times 3}{10} \\ = \frac{3x}{10}$

In second case,

$p = 30000 - x \\ r = 8\% \\ t = 3$

So, simple interest

$= \frac{(30000 - x) \times 8 \times 3}{100} \\ = \frac{(30000 - x) \times 24}{100}$

According to question,

$\frac{3x}{10} + \frac{(30000 - x) \times 24}{100} = 8280 \\ \frac{3x \times 10 + 720000 - 24x}{100} = 8280 \\ \frac{30x + 720000 - 24x}{100} = 8280 \\ \frac{6x + 720000}{100} = 8280 \\ 6x + 720000 = 828000 \\ 6x = 828000 - 720000 \\ 6x = 108000 \\ x = \frac{108000}{6} \\ x = 18000$

Therefore he lent 18000 rupees at 10% rate.

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