Question

a man lift a brick of mass 5 kg from the door to a shelf 2mtrs high much work is done

Answer 1

Because in this case work is done against gravity so we have to use

w=m*g*h

W=work details be

M=5kg

G=9.8m/s²

H=2m

Therefore

W=5*9.8*2

W=98joules

Answer 2

Answer:

Work done, W = 98 joules

Explanation:

It is given that,

Mass of the brick, m = 5 kg

Height above the ground, h = 2 meters

We need to find the work done by the man. It is equal to the gravitational potential energy. Mathematically, it is given by :

$W=mgh$

$W=5\times 9.8\times 2$

W = 98 joules

So, the work done by the man is 98 joules. Hence, this is the required solution.