A man loses 20% of his money. After spending 25% of the remainder, he has ₹ 480 left. How much money did he originally have?
Answers
Answered by
74
Let the original ammount be x
after losing 20% he will be having
(1 - 0.2) = 0.8x
After spending 25%,
he will be having 480 rupees
0.8x × (1 - 0.25) = 480
x = 480/0.6
x = 800
Thanks
Answered by
17
Let the amount of money initially with a man be x
Given,
20% of x => (20/100)×x= 0.2x lost
Remaining Amount = 1 - 0.2x = 0.8x
25% of 0.8x had spent by him
= (25/100)×0.8x
= (1/4)×(8x/10)
= (2x/10)
= 0.2x
Remaining Amount = 0.8x - 0.2x
= 0.6x
Given that this amount is equal to the amount of money left with him
0.6x = 480
=> 6x = 4800
=> x = 800
Therefore Initially man had Rs: 800/-
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