Math, asked by 13812, 6 months ago

a man loses 8% by selling an article for rupees 1449 ,find the cost price and the total loss

Answers

Answered by Anonymous
8

loss% =\frac{loss}{Cost \: price} × 100

loss% =\frac{C.P. - S.P.}{C.P.} × 100

 8 =\frac{C.P. - 1449}{C.P.} × 100

\frac{8}{100}=\frac{C.P - 1449}{C.P}

\frac{2}{25}= (1 -\frac{1449}{C.P.})

\frac{1449}{C.P.}=(1 -\frac{2}{25})

\frac{1449}{C.P.}=\frac{23}{25}

Cost \: Price = 1449 × \frac{25}{23}

Cost \: Price = 63 × 25

Cost \: price = 1575 rupees

Total \: loss=cost \: price - Selling \: price

Total \: loss=1575 - 1449 = 126 rupees

Similar questions