A man loss 20% of his money.he spent 25% of the rest and has left Rs528 with him. How much money he had in the be beginning
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Step-by-step explanation:
Let total money he have be x
he lost 20%of money
now he have
(x-20%of x )
we take 100 in numerator and denominator
=(100x/100-20x/100)
=(80x/100)
let(80x/100)be y
Now,
he spent 25%of rest of his money
(y-25%of y)
=(100y/100-25y/100)
=(75y/100)
=(75/100)(80x/100) because (80x/100=y)
(75/100)(80x/100)=₹528(given in question)
(3/5)(4x/5)=₹528
12x/25=₹528
12x=₹528*25
x=525*25/12
=1093.75
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