Math, asked by adityaraj06072pabhl2, 11 months ago

A man loss 20% of his money.he spent 25% of the rest and has left Rs528 with him. How much money he had in the be beginning​

Answers

Answered by sachinkumar2948
1

Step-by-step explanation:

Let total money he have be x

he lost 20%of money

now he have

(x-20%of x )

we take 100 in numerator and denominator

=(100x/100-20x/100)

=(80x/100)

let(80x/100)be y

Now,

he spent 25%of rest of his money

(y-25%of y)

=(100y/100-25y/100)

=(75y/100)

=(75/100)(80x/100) because (80x/100=y)

(75/100)(80x/100)=₹528(given in question)

(3/5)(4x/5)=₹528

12x/25=₹528

12x=₹528*25

x=525*25/12

=1093.75

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