Math, asked by ghoshmou83, 1 month ago

a man lost 2/3 of his money and then spent 2/3 the remainder after which he had rupees 120 left how much did he lose​

Answers

Answered by peermohamed54362
4

Answer:

STEP 1: Find the fraction of money left after he lost 2/5:

1 - 2/5 = 3/5

STEP 2: Find the fraction of the money he spent:

2/3 x 3/5 = 2/5

STEP 3: Find the fraction of the money he left:

1 - 2/5 - 2/5 = 1/5

STEP 4: Find the amount of money he lose:

1/5 = Rs 1200

2/5 - 1200 x 2 = Rs 2400

Answer: He lost Rs 2400

Answered by BrainlyPARCHO
3

\large { \fcolorbox{gray}{black}{ ✔\: \textbf{Verified \: answer}}}

Total money = x

lost money = 2x/3

Money spent = 2/3 of 2x/3 = 4x/9

Money left = 120

x - (2x/3 + 4x/9) = 120

x - 8x/9 = 120

x/9 = 120

x = 1080

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