Question

A man mass of M is standing on the floor of a lift what his is Apparent weight.(a) when the lift moving in uniform velocity​

Answer 1

Answer:

ǫᴜᴇsᴛɪᴏɴ...

A man mass of M is standing on the floor of a lift what his is Apparent weight.(a) when the lift moving in uniform velocity..

ᴀɴsᴡᴇʀ..

When lift accelerates up, pseudo force acts downwards, hence it increases apparent weight. [a-e]

When lift accelerates down, pseudo force acts upwards, hence it decreases apparent weight [b-h]

When lift moves with uniform velocity there is no pseudo force, hence there is no change in weight. [c-g]

When lift falls freely, it accelerates with g downwards, causing an upwards pseudo force in the frame of the lift equal to mg. Hence total force is 0. So weight is 0. [d-f]

Answer 2

Answer:

This is because, in uniform velocity, the velocity doesn't change. Hence the acceleration produced is equal to zero. Therefore, no pseudo force acts on the man travelling on the lift. Hence his apparent weight would remain equal to his true weight which is Mg.

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