Question

A man misses a bus by 20
minutes if he travels at speed
of 52 km/ hr. If he travel at
65 km/hr ,he reaches early by 10
minutes. What is the speed at
which the man has to travel
to reach the bus stop on time?​

Answer 1

Answer:

260

Step-by-step explanation:

i hope it is correct bro

Answer 2

let distance be= x

Ist day time=distance/speed

=x/52hr

IInd day time=distance/speed

=x/65hr

$x \div 52 - 20\div 60 = x \div 65 + 10\div 60$

$x \div 52 - x \div 65 =20 + 10 \div 60$

$5x - 4x \div 260 = 1 \div 2$

cross multiply

$x = 260 \div 2$

$x = 130km$