Math, asked by samm83, 1 year ago

a man mix 50 kg of tea at a lower price with 30 kg of tea at a higher price and selling the mixture at rupees 78.7 5 per kg he gains 20% if the difference of the cost prices of the two teas be rs 15 find the cost of each tea per kg.​

Answers

Answered by subhrajyotibera1999
4

75,60

let,lower price = x

higher price = (x+15)

mixture cost price = 78.75*(100÷120)

=(262.5/4)

mixture cost price = 50*lower price + 30*higher price

(262.5/4)=50*x+30*(x+15)

×=60

lower price=60

higher price=75

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