Math, asked by rohan4979, 11 months ago

a man mixes 90litres of milk containing 10%of water and 60 litres of milk containing 20%of water. what is the percentage of water in the mixture?​

Answers

Answered by altmash280
12

Answer:

quantity of water in 90 liters mixture

= 90×10%

=90×10/100

=9liters water

quantity of watrr in 60 litres mixture

=60×20%

=60×20/100

=12 liters

Total quantity of mixture

=90+60

=150 litres

Total quantity of water

=12+9

=21 liter

Percentage of water in mixture

=21×100/150

=14%

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Answered by riyakumari01410
0

Answer:

14%

Step-by-step explanation:

quantity of water in 90gallon=90×10%

=90×10/100=9 litres

quantity of water in 60gallon=60×20

60*20/100=12 litres

total quantity of wine=90+60=150

total quantity of water in the mixture=12+9=21

%of water in mixture=21*100/150

=7*2

=14%

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