Question

A man moves 100 m 30° East of south then
another 100 m 60° North of East .His distance and displacementfrom starting point?​

Answer 1

Answer:

Displacement= 36.6m And Distance = 136.6m.

Explanation:

Lateral Distance Of 100m 30° East of South= cos(30°)×100= 86.6m.

Lateral Distance Of 100m 60° North of East= cos(60°)×100= 50m.

Total Displacement= 86.6-50= 36.6m

Distance = 86.6+50= 136.6m