Question

A man moves 200km towards north-east direction.taking i and j as unit vectors along east and north directions respectively, find the displacement of the man along north and east directions.

Answer 1

Here is ur answer...

Hope it helps...

Plz mark me as brainliest...

Answer 2

Answer:

Explanation:

Concept:

Definition of displacement:

The term "displacement" refers to a shift in an object's position. It is a vector quantity with a magnitude and direction. The symbol for it is an arrow pointing from the initial location to the ending place. For instance, if an object shifts from location A to position B, its position changes. Displacement is the term used to describe this shift in an object's position.

Definition of distance:

Distance is the sum of an object's movements, regardless of direction. Distance can be defined as the amount of space an object has covered, regardless of its starting or ending position.

Definition of unit vector:

A quantity with both magnitude and direction is referred to as a vector. A unit vector is one with a magnitude of 1. It also goes by the name Direction Vector.

Given:

A man moves 200km towards north-east direction.

taking i and j as unit vectors

Find:

displacement

Solution:

$S1 = 200 cos 45 i$

$S2 = 200 cos 45 j$

$S1 = 200 cos(1/\sqrt2) i$

$S2 = 200 cos (1/\sqrt2) j$

$S1 = 100\sqrt 2 cos i$

$S 2 = 100 \sqrt2 cos j$

$S = S1 + S2$

$S = 100 \sqrt 2 cos i + 100 \sqrt 2 cosj$

Hence the displacement of the man along north and east direction is

$S = 100 \sqrt 2 cos i + 100 \sqrt 2 cosj$

#SPJ2