Question

A man moves 20m north, then 10m east and then 102m south-west. His displacement is
a. 20 m north
b. 10√2m north-west
c. 10 m north
d. 10√2m south-east
Explain the why answer is option C.
PLEASE ANSWER WITH EXPLAINATION..

ANSWER IS option C....​

Answer 1

Answer:

10m north

Explanation:

hope it is helpful for you

Answer 2

Correct Question :

A man moves 20m north, then 10m east and then 10√2m south-west. His displacement is...

Answer :

Displacement is defined as the shortest distance between initial and final position of the entire journey$.$

It is a vector quantity having both magnitude as well as direction.

Let man starts his journey from origin.

1. He moves 20m north.

(see the line OA = 20m)

2. Then he moves 10m east.

(see the line AB = 10m)

3. Then he moves 10√2m south-west.

(see the line BC = 10√2m)

As per pythagoras theorem,

➝ AC² + AB² = BC²

➝ AC² + 10² = (10√2)²

➝ AC² = 200 - 100

➝ AC² = 100

➝ AC = 10m

$\star$ Displacement = OA - AC

• 20 - 10
• 10m in north

∴ (C) is the correct answer!