Question

a man moves A to B 200 m in 2 min and then turn back and move to c 50m in 1 min find average velocity of speed​

Answer 1

Answer:

When t=1, the velocity of the particle is 4+2=6 m/s. When t=2, the velocity of the particle is 4+2×2=8 m/s. After t seconds, the velocity of the particle is 4+2t m/s.

Answer 2

Answer:

Average Velocity=50m/s

Explanation:

Question:-

A man moves A to B 200 m in 2 min and then turn back and move to c 50m in 1 min find average velocity of speed.

Solution:-

• Average Velocity:- Total displacement/Total time taken

: Vavg=200-50/3

:Vavg=150/3

:Vavg=50m/s