A man moves along a square field of side 10 m. If he takes 8 seconds to complete one round,
what will be the distance covered and displacement after 40 s
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Answer:
required distance = 200 m and displacement = 0
Explanation:
Side of square field a = 10 m
Distance covered in one round = perimeter
= 4a
= 40 m
Number of rounds in 40 s = (40/8) = 5 rounds
∴ Distance covered in 40 s = 40 x 5 = 200 m
In 40 s after 5 rounds the particle reaches the initial position.
∴ displacement in 40 s = 0
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