Physics, asked by vslnaarayanan2017, 10 months ago

A man moves by 4 m then turns to his right by 3 m and got in to a loft and moves by 12 m. Calculate distance and displacement of the man.

Answers

Answered by anusy2850
3

Answer:

hiii!!!

here's ur answer....

first, the man moves 4m along East direction and then 3m along north direction. it formed a right angle triangle.

let the base be 4m and height be 3m

by Pythagoras theorem :-

= √(4²+3²)

= √(16+9)

= √25

= 5m

after going to North direction, the man climbs up a pole of height 12m. again it formed a right angle triangle and now the hypotenuse is the displacement

now let the base be 5m and height be 12m.

by Pythagoras theorem :-

displacement = √(5²+12²)

= √(25+144)

= √169

= 13

hence, total distance covered by him = 3 + 4 + 12 = 19m and displacement = 13m

hope this helps..!!

Explanation:

Answered by Anonymous
1

hope it helps you..please mark me as brailiest...

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