A man moves from A to B at the rate of 4 km an hour. Had he moved at the rate of 3(2/3) km an hour, he would have taken 3 hours more to move that distance. Find the distance between A and B
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Let D be the distance,distance=speed*time
Therefore,
D=4t=(11/3)(t+3)
=>4t=(11/3)t+11
=>(1/3)t=11
=>t=33
Therefore,
D=4*t=4*33=132km
If the second speed is 3*(2/3)=2km/hr
Therefore,
4t=2(t+3)
=>t=3km/hr
Therefore,
D=4*3=12 km/hr.
Therefore,
D=4t=(11/3)(t+3)
=>4t=(11/3)t+11
=>(1/3)t=11
=>t=33
Therefore,
D=4*t=4*33=132km
If the second speed is 3*(2/3)=2km/hr
Therefore,
4t=2(t+3)
=>t=3km/hr
Therefore,
D=4*3=12 km/hr.
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