Question

A man moves on a horizontal road towards east at
a speed of 1 km/hr and the rain appears to him
vertical at a speed of 2 km/hr. The actual speed of
the rain (in km/hr) is​

Answer 1

Vr/m=Vr/g-Vm/g

• Vr/m=underroot Vr/g2+Vm/g2
• underroot 2 square+underroot 1 square
• underroot 5
• =2.75

Answer 2

Hello Dear,

◆ Answer -

|vr| = √5 km/hr

◆ Explaination -

# Given -

|vm| = 1 km/hr

|vrm| = 2 km/hr

# Solution -

Relative velocity of rain w.r.t. man is -

vrm = vr - vm

vr = vrm + vm

In terms of magnitude,

|vr| = √(|vrm|² + |vr|²)

|vr| = √(2² + 1²)

|vr| = √(4 + 1)

|vr| = √5 km/hr

Therefore, actual speed of the rain must be √5 km/hr.

Thanks dear...