Physics, asked by Anonymous, 11 months ago

a man moves on a semicircular track of radius 40m. if he starts at 1 end of track and reaches the other end , find distance covered by him and his displacement .

Answers

Answered by LORD4688
5
Distance = π × r= 40×π = 125.66 meters

Displacement = shortest path = diameter
= 40× 2 = 80 meters

Anonymous: ur answer is right Sir. ... very sorry...thank u so very much...!
Similar questions