A man moves on a straight horizontal road with a block of mass 2kg in his hands. If he covers a distance of 40 m with an acceleration of 0.5 ms-2 , find the work done by man on block during the motion
Answers
Answered by
106
Given ;
•mass of a block = 2 kg
•acceleration of a block
= acceleration of a man
= 0.5 m/s^2
• Displacement = 40 m
F = ma
F = 2×0.5
F = 1 N
Work Done = Force×Displacement
= 1×40
= 40 J
____________________
•mass of a block = 2 kg
•acceleration of a block
= acceleration of a man
= 0.5 m/s^2
• Displacement = 40 m
F = ma
F = 2×0.5
F = 1 N
Work Done = Force×Displacement
= 1×40
= 40 J
____________________
Answered by
31
Answer: work =40J
Explanation:
Given,
m=2 kg
a=0.5 m/s
S=40m
Solution,,,,
F=m×a
F=2×0.5
F= 1N
Work, W=F×S
W=1×40
W=40J
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